I was talking about the slight curvature remaining in your vacuum spin decay curves (SDCs)
So, what slight curvature ? The curvatures that you see are due to the tip friction that changes during the spin, especially without oil and for heavier tops.
The residual air pressure in the vacuum chamber, no more than 0.5 mm hg, produced an air drag that is no more than 1/300 of that at the normal air pressure. What is the sense of becoming obsessed about that 0.3% error, when we are dealing with an impredictable tip friction variability which is normally far larger ?
Perhaps I should have been clearer. In my mind, a spin decay curve (SDC) is a raw plot of angular speed vs. time. The slope of an SDC at any time t is proportional to the total braking torque (TBT) acting on the test top at that time.
"Total" here means the net torque from all resistances present — regardless of their physical causes. There's no way around this.
A straight line in an SDC has a constant slope indicating a constant TBT, as you'd expect from, say, pure sliding friction at the tip in the complete absence of air resistance. Such friction has no speed dependence.
Any departure from a straight line in an SDC points to a speed-dependent TBT. A sagging (convex-downward) SDC — the kind we see in air — has an ever-decreasing slope, indicating an ever-decreasing TBT, as you'd expect when the TBT is dominated by, say, air resistance or the viscous torque from tip lube.
The last linear plot you showed is
not an SDC. It's a plot of TBT vs. speed, and whatever the cause, the TBT nearly doubled between between 200 and 1,300 RPM. If that plot is based
solely on speed vs. time data, then the underlying SDC
must sag. No way around this.
May we see that raw SDC, please?
These are all kinematic observations. They don't settle the underlying dynamics, meaning that they don't by themselves identify the torques making up the TBT. The dynamics are a matter of interpretation based on what we know or theorize about the various resistances involved.