It appears to me, that diameter is nearly irrelevant at higher speeds in air.
At a given RPM the surface velocity at the perimeter of a top is proportional to diameter and aero drag (at very low Reynold's numbers) is proportional to velocity. So the aero drag at the perimeter would be proportional to D^2. Then the surface area of the perimeter increases with diameter, so we have aero drag at the perimeter proportional to D^3. Furthermore, the perimeter's braking torque at the axis is proportional to D. So we have total braking torque = D^4. This is only countered by inertia, which equals diameter squared. This leads to D^4 / D^2 = D^2 as a decay factor for diameter. That is larger decays faster.
Despite that, when I compared two 48 gram tops, both on 3/8" balls, with diameters of 1" and 2", their decays in the range of 800 to 1,000 RPM were about equal.
I also compared 1" and 1.25" tops of the same weight and ball diameter, but closer in configuration than the 2" above. In the range of 1,000 to 1,400 RPM, the 1.25" top has slightly lower decay.
Of course diameter helps at low speed.
Alan